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(A) Let $F$ be the set of people who speak French and $S$ be the set of people who speak Spanish.Given:$n(F) = 50$$n(S) = 20$$n(S \cap F) = 10$We need

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$60$

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(A) Let $F$ be the set of people who speak French and $S$ be the set of people who speak Spanish.Given:$n(F) = 50$$n(S) = 20$$n(S \cap F) = 10$We need to find the number of people who speak at least one of these two languages,which is $n(S \cup F)$.Using the formula:$n(S \cup F) = n(S) + n(F) - n(S \cap F)$Substituting the values:$n(S \cup F) = 20 + 50 - 10$$n(S \cup F) = 70 - 10 = 60$Thus,$60$ people speak at least one of these two languages.

In a committee,$50$ people speak French,$20$ speak Spanish and $10$ speak both Spanish and French. How many speak at least one of these two languages?

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