In a common base amplifier,the phase difference between the input signal voltage and the output voltage is

In a $CE$ transistor amplifier,there is a current and voltage gain associated with the circuit. In other words,there is a power gain. Considering power as a measure of energy,does the circuit violate the law of conservation of energy?

An oscillator is nothing but an amplifier with

The transfer characteristics [output voltage $(V_o)$ vs input voltage $(V_i)$] for a base-biased transistor in $CE$ configuration are shown in the figure. For using a transistor as a switch,it is used:

In $n-p-n$ transistor, in $CE$ configuration:

$A$ transistor is connected in common emitter circuit configuration. The collector supply voltage is $10 \, V$ and the voltage drop across a resistor of $1000 \, \Omega$ in the collector circuit is $0.6 \, V$. If the current gain factor $(\beta)$ is $24$,then the base current is $.... \, \mu A$. (Round off to the Nearest Integer)