In a common emitter amplifier of a transistor,if the ratio of the voltage gain and current amplification factor is $4$,then the ratio of the collector and base resistances is

In a $CE$ transistor, a change of $8.0 \,mA$ in the emitter current produces a change of $7.8 \,mA$ in the collector current. What change in the base current is necessary to produce the same change in the collector current (in $\mu A$)?

The current amplification factor of a transistor is $50$. The input resistance when used in common emitter mode is $1 \text{ k}\Omega$. The peak value of the collector current for an a.c. input voltage of $0.01 \text{ V}$ peak is:

In an $N-P-N$ transistor circuit,the common emitter configuration is used. $A$ load resistor $R_L$ is connected to the collector and a base resistor $R_B$ is connected to the base. Given $V_{CC} = 8V$,$V_{CE} = 4V$,$V_{BE} = 0.6V$,collector current $I_C = 4mA$,and current gain $\beta = 100$,find the values of $R_L$ and $R_B$ respectively.

In a common emitter transistor amplifier,the audio signal voltage across the collector is $3\,V$. The resistance of the collector is $3\,k\Omega$. If the current gain is $100$ and the base resistance is $2\,k\Omega$,what are the voltage and power gain of the amplifier?

In the circuit shown in the figure,the current gain $\beta = 100$ for an $npn$ transistor. What should be the base resistor $R_B$ so that $V_{CE} = 5 \text{ V}$,given $V_{BE} = 0 \text{ V}$?