In the circuit shown in the figure,the current gain $\beta = 100$ for an $npn$ transistor. What should be the base resistor $R_B$ so that $V_{CE} = 5 \text{ V}$,given $V_{BE} = 0 \text{ V}$?

In the case of constants $\alpha$ and $\beta$ of a transistor:

$A$ common emitter amplifier circuit is shown in the figure. For the transistor used in the circuit,the current amplification factor is $\beta_{dc} = 100$. Other parameters are given in the figure.

For a transistor,the current ratio $\beta_{dc}$ is defined as the ratio of:

Consider an amplifier circuit wherein a transistor is used in common emitter mode. The change in collector current and base current respectively are $4 mA$ and $20 \mu A$ when a signal of $40 mV$ is added to the base-emitter voltage. If the load resistance is $10 k\Omega$, then the power gain in the circuit is:

In the following circuit, a voltmeter $V$ is connected across a lamp $L$. What change would occur in the voltmeter reading if the resistance $R$ is reduced in value?