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(D) For a transistor,$\alpha$ (common-base current gain) is defined as the ratio of collector current $(I_C)$ to emitter current $(I_E)$,i.e.,$\alpha

Vedclass · Accepted Answer

$\beta > 1, \alpha < 1$

Vedclass · Answer

(D) For a transistor,$\alpha$ (common-base current gain) is defined as the ratio of collector current $(I_C)$ to emitter current $(I_E)$,i.e.,$\alpha = \frac{I_C}{I_E}$. Since $I_E = I_C + I_B$,it follows that $I_C $\beta$ (common-emitter current gain) is defined as the ratio of collector current $(I_C)$ to base current $(I_B)$,i.e.,$\beta = \frac{I_C}{I_B}$. Since the base current $I_B$ is very small compared to the collector current $I_C$,$\beta$ is typically much greater than $1$.Therefore,the correct relationship is $\alpha  1$.

In the case of constants $\alpha$ and $\beta$ of a transistor:

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