In a common emitter transistor amplifier circuit,the current gain $\alpha = 0.8$. If the base current changes by $3 \mu A$,then the collector current changes by: (in $\mu A$)

In the following common emitter configuration, an $NPN$ transistor with current gain $\beta = 100$ is used. The output voltage of the amplifier will be

What is the power gain in a $CE$ amplifier,where the input resistance is $3\,k\Omega$ and the load resistance is $24\,k\Omega$,given $\beta = 20$?

In the study of a transistor as an amplifier,if $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$,where $I_{C}$,$I_{B}$,and $I_{E}$ are the collector,base,and emitter currents respectively,then:

For a transistor,$\alpha$ and $\beta$ are given as $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$. Then the correct relation between $\alpha$ and $\beta$ is:

For a common base circuit,if $\frac{I_C}{I_E} = 0.98$,then the current gain for a common emitter circuit will be: