In a common emitter transistor amplifier,the output voltage and input voltage have a phase difference of

In a common emitter amplifier,the output resistance is $5000 \Omega$ and the input resistance is $2000 \Omega$. If the peak value of input signal voltage is $100 mV$ and $\beta=50$,then the peak value of output voltage is

$A$ transistor having $\alpha = 0.99$ is used in a common base amplifier. If the load resistance is $4.5 \, k\Omega$ and the dynamic resistance of the emitter junction is $50 \, \Omega$,the voltage gain of the amplifier will be:

In the case of $NPN$ transistors,the collector current is always less than the emitter current because:

For a common base configuration of a $PNP$ transistor,$\frac{I_C}{I_E} = 0.96$. Then,the maximum current gain in common emitter configuration will be:

In common emitter mode of a transistor, the current gain is $8$. The input impedance is $25 \, k\Omega$ and load resistance is $75 \, k\Omega$. The power gain is