In a common emitter configuration, a transistor has $\beta=50$ and input resistance $1 \text{ k}\Omega$. If the peak value of a.c. input is $0.01 \text{ V}$, then the peak value of collector current is: (in $\mu\text{A}$)

The given transistor operates in the saturation region. What should be the value of $V_{BB}$ (in $Volt$)?
$(R_{out} = 200 \, \Omega, R_{in} = 100 \, k\Omega, V_{CC} = 3 \, V, V_{BE} = 0.7 \, V, \beta = 200)$

For a $CE$ transistor amplifier,the audio signal voltage across the collector resistance of $2.0\,k\Omega$ is $2.0\,V$. Suppose the current amplification factor of the transistor is $100$. What should be the value of $R_B$ (in $k\Omega$) in series with $V_{BB}$ supply of $2.0\,V$ if the $dc$ base current has to be $10$ times the signal current?

If $\alpha$ and $\beta$ are the current gains in the $CB$ and $CE$ configurations respectively of the transistor circuit,then $\frac{\beta - \alpha}{\alpha \beta} = $

Three terminals of a transistor,denoted by $P, Q,$ and $R,$ are tested using a multimeter. No conduction occurs between $P$ and $Q.$ When the negative lead of the multimeter is connected to $R$ and the positive lead is connected to either $P$ or $Q,$ the meter shows some resistance. Which of the following options is correct for the given transistor?

In the study of a transistor as an amplifier,if $\alpha = \frac{I_C}{I_E} = 0.98$ and $\beta = \frac{I_C}{I_B} = 49$,where $I_C, I_B,$ and $I_E$ are collector,base,and emitter currents respectively,then $\left(\frac{1}{\alpha} - \frac{1}{\beta}\right)$ is equal to: