In a double-slit experiment,the angular width | vedclass

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Question

(A) The angular width of a fringe in a double-slit experiment is given by $	heta = \frac{\lambda}{d}$,where $\lambda$ is the wavelength of light and

Vedclass · Accepted Answer

$0.15$

Vedclass · Answer

(A) The angular width of a fringe in a double-slit experiment is given by $	heta = \frac{\lambda}{d}$,where $\lambda$ is the wavelength of light and $d$ is the slit separation.When the apparatus is immersed in a medium of refractive index $\mu$,the wavelength of light changes to $\lambda' = \frac{\lambda}{\mu}$.Consequently,the new angular width $	heta'$ becomes $	heta' = \frac{\lambda'}{d} = \frac{\lambda}{\mu d} = \frac{	heta}{\mu}$.Given $	heta = 0.2^{\circ}$ and $\mu = 4/3$,the new angular width is:$	heta' = \frac{0.2^{\circ}}{4/3} = 0.2^{\circ} 	imes \frac{3}{4} = 0.15^{\circ}$.Thus,the angular width of the fringe in water is $0.15^{\circ}$.

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