In a family,mother's age is twice that of dau | vedclass

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(B) Let the age of the daughter be $x$ years.According to the problem,the brother is $5$ years older than the sister (daughter),so the brother's age i

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$60$

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(B) Let the age of the daughter be $x$ years.According to the problem,the brother is $5$ years older than the sister (daughter),so the brother's age is $(x + 5)$ years.The brother is also $20$ years younger than the mother,which means the mother's age is $(x + 5 + 20) = (x + 25)$ years.We are also given that the mother's age is twice the daughter's age,so $2x = x + 25$.Solving for $x$: $2x - x = 25$,which gives $x = 25$ years.Thus,the mother's age is $2 	imes 25 = 50$ years.The father is $10$ years older than the mother,so the father's age is $50 + 10 = 60$ years.

In a family,mother's age is twice that of daughter's age. Father is $10 \,years$ older than mother. Brother is $20 \,years$ younger than his mother and $5 \,years$ older than his sister. What is the age of the father? (in $years$)

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