The age of the father $10 \,years$ ago was thrice the age of his son. Ten $years$ hence,father's age will be twice that of his son. The ratio of their present age is

$3 \text{ years}$ ago,the average age of a family of $5$ members was $17 \text{ years}$. $A$ baby having been born,the average age of the family is the same today. What is the age of the child? (in $\text{years}$)

The ages of $A$ and $B$ are in the ratio $6: 5$ and the sum of their ages is $44 \text{ years}$. The ratio of their ages after $8 \text{ years}$ will be:

$A$ father is aged three times more than his son Ronit. After $8 \, \text{years}$,he would be two and a half times of Ronit's age. After further $8 \, \text{years}$,how many times would he be of Ronit's age?

In a family,a couple has a son and a daughter. The age of the father is three times that of his daughter and the age of the son is half of his mother. The wife is $9$ years younger than her husband and the brother is $7$ years older than his sister. What is the age of the mother? (in years)

The ages of $A, B$ and $C$ together is $185$ years. $B$ is twice as old as $A$ and $C$ is $17$ years older than $A$. Then,the respective ages of $A, B$ and $C$ are (in years):