(B) For the first diffraction minimum,the condition is given by $a \sin \theta = n\lambda$. For $n=1$,$a \sin \theta = \lambda$.Given $\theta = 30^{\c

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$\sin^{-1}\left(\frac{3}{4}\right)$

(B) For the first diffraction minimum,the condition is given by $a \sin \theta = n\lambda$. For $n=1$,$a \sin \theta = \lambda$.Given $\theta = 30^{\circ}$,we have $a = \frac{\lambda}{\sin 30^{\circ}} = 2\lambda$.For the first secondary maximum,the condition is $a \sin \theta' = \frac{3\lambda}{2}$.Substituting the value of $a = 2\lambda$ into the equation:$2\lambda \sin \theta' = \frac{3\lambda}{2}$$\sin \theta' = \frac{3\lambda}{2 \times 2\lambda} = \frac{3}{4}$.Therefore,$\theta' = \sin^{-1}\left(\frac{3}{4}\right)$.

Class 12 Physics Wave Optics Fresnel distance, Diffraction through circular slit, concept of Airy Disc, Rayleigh Criterion of Resolution , Fraunhofer diffraction

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In a Fraunhofer diffraction experiment at a single slit using light of wavelength $400 \ nm$,the first minimum is formed at an angle of $30^{\circ}$. The direction $\theta'$ of the first secondary maximum is given by

KCET 2008 All KCET

A
$\sin^{-1}\left(\frac{2}{3}\right)$
B
$\sin^{-1}\left(\frac{3}{4}\right)$
C
$\sin^{-1}\left(\frac{1}{4}\right)$
D
$\tan^{-1}\left(\frac{2}{3}\right)$

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Wave Optics

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Fresnel distance, Diffraction through circular slit, concept of Airy Disc, Rayleigh Criterion of Resolution , Fraunhofer diffraction

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In a Fraunhofer diffraction experiment at a single slit using light of wavelength $400 \ nm$,the first minimum is formed at an angle of $30^{\circ}$. The direction $\theta'$ of the first secondary maximum is given by

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