In a game,two players $A$ and $B$ take turns throwing a pair of fair dice,starting with player $A$. The total score on the two dice in each throw is noted. $A$ wins the game if he throws a total of $6$ before $B$ throws a total of $7$,and $B$ wins the game if he throws a total of $7$ before $A$ throws a total of $6$. The game stops as soon as either of the players wins. The probability of $A$ winning the game is:

  • A
    $\frac{31}{61}$
  • B
    $\frac{5}{6}$
  • C
    $\frac{5}{31}$
  • D
    $\frac{30}{61}$

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