In a hydrogen atom,an electron moves in a cir | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The magnetic field $B$ at the center of a circular current loop is given by the formula: $B = \frac{\mu_0 i}{2r}$.Given values are: $B = 12.56 \,

Vedclass · Accepted Answer

$1.04 	imes 10^{-3} \, A$

Vedclass · Answer

(D) The magnetic field $B$ at the center of a circular current loop is given by the formula: $B = \frac{\mu_0 i}{2r}$.Given values are: $B = 12.56 \, T$,$r = 5.2 	imes 10^{-11} \, m$,and $\mu_0 = 4\pi 	imes 10^{-7} \, T \cdot m/A$.Substituting these values into the formula:$12.56 = \frac{(4\pi 	imes 10^{-7}) 	imes i}{2 	imes 5.2 	imes 10^{-11}}$$12.56 = \frac{2\pi 	imes 10^{-7} 	imes i}{5.2 	imes 10^{-11}}$Using $\pi \approx 3.14$,we have $2\pi \approx 6.28$.$12.56 = \frac{6.28 	imes 10^{-7} 	imes i}{5.2 	imes 10^{-11}}$$i = \frac{12.56 	imes 5.2 	imes 10^{-11}}{6.28 	imes 10^{-7}}$$i = 2 	imes 5.2 	imes 10^{-4} \, A$$i = 10.4 	imes 10^{-4} \, A = 1.04 	imes 10^{-3} \, A$.

In a hydrogen atom,an electron moves in a circular orbit of radius $5.2 \times 10^{-11} \, m$ and produces a magnetic induction of $12.56 \, T$ at its nucleus. The current produced by the motion of the electron will be (Given $\mu_0 = 4\pi \times 10^{-7} \, Wb/A \cdot m$)

Similar Questions

Current $I$ is flowing in a conductor shaped as shown in the figure. The radius of the curved part is $r$ and the length of the straight portions is very large. The value of the magnetic field at the centre $O$ will be

Two points $A$ and $B$ on the axis of a circular current loop are at distances of $4 \ cm$ and $3 \sqrt{3} \ cm$ from the centre of the loop. If the ratio of the induced magnetic fields at points $A$ and $B$ is $216: 125$, the radius of the loop is (in $cm$)

The magnetic field at a distance $r$ from a long straight wire carrying current $i$ is $0.4 \ T$. The magnetic field at a distance $2r$ is: (in $T$)

An electron of mass $m$ is revolving around the nucleus in a circular orbit of radius $r$ and has angular momentum $L$. The magnetic field produced by the electron at the centre of the orbit is ($e = \text{electric charge}$, $\mu_{0} = \text{permeability of free space}$)

$A$ current $I$ flows through the loop as shown in the figure. The magnetic field at the centre $O$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module