In a hydrogen atom,an electron makes a transi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Bohr's postulate,the angular momentum $L$ of an electron in the $n^{	ext{th}}$ orbit is given by $L = \frac{nh}{2\pi}$.For the $5^{\

Vedclass · Accepted Answer

$\frac{h}{\pi}$

Vedclass · Answer

(B) According to Bohr's postulate,the angular momentum $L$ of an electron in the $n^{	ext{th}}$ orbit is given by $L = \frac{nh}{2\pi}$.For the $5^{	ext{th}}$ orbit $(n_1 = 5)$,the angular momentum is $L_5 = \frac{5h}{2\pi}$.For the $3^{	ext{rd}}$ orbit $(n_2 = 3)$,the angular momentum is $L_3 = \frac{3h}{2\pi}$.The change in angular momentum $\Delta L$ is given by:$\Delta L = L_5 - L_3$$\Delta L = \frac{5h}{2\pi} - \frac{3h}{2\pi}$$\Delta L = \frac{h}{2\pi} (5 - 3)$$\Delta L = \frac{2h}{2\pi} = \frac{h}{\pi}$.

In a hydrogen atom,an electron makes a transition from the $5^{\text{th}}$ orbit to the $3^{\text{rd}}$ orbit. The change in the angular momentum for this electron is . . . . . . .

Similar Questions

The orbital magnetic moment $(m_{orb})$ of a revolving electron around the nucleus varies with the principal quantum number $(n)$ as

The radius of the innermost electron orbit of a hydrogen atom is $5.3 \times 10^{-11} \text{ m}$. What is the radius of the $n = 3$ orbit?

The electron of a hydrogen atom makes a transition from the $(n + 1)^{th}$ orbit to the $n^{th}$ orbit. For large $n$,the wavelength of the emitted radiation is proportional to:

The ratio of the kinetic energy to the total energy of an electron in a Bohr orbit is

$A$ Hydrogen atom and a $Li^{++}$ ion are both in the second excited state. If $l_H$ and $l_{Li}$ are their respective electronic angular momenta,and $E_H$ and $E_{Li}$ are their respective energies,then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module