In a rectangle $ABCD$,the coordinates of $A$ and $B$ are $(1, 2)$ and $(3, 6)$ respectively,and some diameter of the circumscribing circle of $ABCD$ has the equation $2x - y + 4 = 0$. Then,the area of the rectangle is

  • A
    $16$
  • B
    $2 \sqrt{10}$
  • C
    $2 \sqrt{5}$
  • D
    $20$

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