(C) For a closed organ pipe (resonance tube),the resonance lengths are given by $l_n = (2n - 1) \frac{\lambda}{4}$,where $n = 1, 2, 3, \dots$For the f

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(C) For a closed organ pipe (resonance tube),the resonance lengths are given by $l_n = (2n - 1) \frac{\lambda}{4}$,where $n = 1, 2, 3, \dots$For the first resonance $(n=1)$,$l_1 = \frac{\lambda}{4} = 16\,cm$.For the second resonance $(n=2)$,$l_2 = 3 \frac{\lambda}{4} = 3 \times 16 = 48\,cm$.Thus,the next resonance is obtained at $48\,cm$.

Class 11 Physics Waves and Sound Longitudinal Stationary Waves (Organ Pipes) and Resonance Tube

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In a resonance tube,the first resonance is obtained when the level of water in the tube is at $16\,cm$ from the open end. Neglecting end correction,the next resonance will be obtained when the level of water from the open end is .... $cm$

A
$24$
B
$32$
C
$48$
D
$64$

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Waves and Sound

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Longitudinal Stationary Waves (Organ Pipes) and Resonance Tube

The length of an open organ pipe is twice the length of another closed organ pipe. The fundamental frequency of the open pipe is $100 \ Hz$. The frequency of the third harmonic of the closed pipe is ..... $Hz$.

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$A$ cylindrical tube open at both ends has a fundamental frequency '$n$' in air. The tube is dipped vertically in water so that one-fourth of it is in water. The fundamental frequency of the air column becomes

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$A$ pipe closed at one end produces a fundamental note of $412 \, Hz$. It is cut into two pieces of equal length. The fundamental notes produced by the two pieces are:

Medium

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Four open organ pipes of different lengths and different gases at the same temperature are shown in the figure. Let $f_A$,$f_B$,$f_C$,and $f_D$ be their fundamental frequencies. Then: [Take $\gamma_{CO_2} = 7/5$]

Medium

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In a closed organ pipe, the number of nodes formed in the fifth and ninth harmonics are respectively:

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In a resonance tube,the first resonance is obtained when the level of water in the tube is at $16\,cm$ from the open end. Neglecting end correction,the next resonance will be obtained when the level of water from the open end is .... $cm$

Similar Questions

The length of an open organ pipe is twice the length of another closed organ pipe. The fundamental frequency of the open pipe is $100 \ Hz$. The frequency of the third harmonic of the closed pipe is ..... $Hz$.

$A$ cylindrical tube open at both ends has a fundamental frequency '$n$' in air. The tube is dipped vertically in water so that one-fourth of it is in water. The fundamental frequency of the air column becomes

$A$ pipe closed at one end produces a fundamental note of $412 \, Hz$. It is cut into two pieces of equal length. The fundamental notes produced by the two pieces are:

Four open organ pipes of different lengths and different gases at the same temperature are shown in the figure. Let $f_A$,$f_B$,$f_C$,and $f_D$ be their fundamental frequencies. Then: [Take $\gamma_{CO_2} = 7/5$]

In a closed organ pipe, the number of nodes formed in the fifth and ninth harmonics are respectively:

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