In a saturated solution of Mg(OH)_2,the degre | vedclass

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(C) The dissociation of $Mg(OH)_2$ is represented as: $Mg(OH)_2 \rightleftharpoons Mg^{2+} + 2OH^{-}$ Let the initial concentration of $Mg(OH)_2$ be $

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$1/\alpha$

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(C) The dissociation of $Mg(OH)_2$ is represented as: $Mg(OH)_2 \rightleftharpoons Mg^{2+} + 2OH^{-}$ Let the initial concentration of $Mg(OH)_2$ be $C$ and the degree of dissociation be $\alpha$. According to the stoichiometry of the reaction,the concentration of hydroxide ions is given by: $[OH^{-}] = 2C\alpha$ Given that $[OH^{-}] = 2$,we can write: $2C\alpha = 2$ Dividing both sides by $2\alpha$,we get: $C = 1/\alpha$

In a saturated solution of $Mg(OH)_2$,the degree of dissociation of $Mg(OH)_2$ is $\alpha$. Find the concentration $(C)$ of $Mg(OH)_2$ if the concentration of $[OH^{-}]$ is $2$.

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