In a set of reactions,ethylbenzene yielded a | vedclass

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(C) $1$. Oxidation: Ethylbenzene reacts with alkaline $KMnO_4$ to form benzoic acid $(B)$. The alkyl group is oxidized to a $-COOH$ group.$2$. Bromina

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Ethyl $3-$bromobenzoate

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(C) $1$. Oxidation: Ethylbenzene reacts with alkaline $KMnO_4$ to form benzoic acid $(B)$. The alkyl group is oxidized to a $-COOH$ group.$2$. Bromination: Benzoic acid is a meta-directing group. Reaction with $Br_2/FeCl_3$ yields $3-$bromobenzoic acid $(C)$.$3$. Esterification: $3-$bromobenzoic acid reacts with ethanol $(C_2H_5OH)$ in the presence of an acid catalyst $(H^+)$ to form ethyl $3-$bromobenzoate $(D)$.

In a set of reactions,ethylbenzene yielded a product $D$.
Ethylbenzene $\xrightarrow[KOH]{KMnO_4} B$ $\xrightarrow[FeCl_3]{Br_2} C$ $\xrightarrow[H^{+}]{C_2H_5OH} D$
$D$ would be

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In a set of reactions,ethylbenzene yielded a product $D$.Ethylbenzene $\xrightarrow[KOH]{KMnO_4} B$ $\xrightarrow[FeCl_3]{Br_2} C$ $\xrightarrow[H^{+}]{C_2H_5OH} D$$D$ would be