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(C) The distance between the first minima on both sides of the central maximum in a single slit diffraction pattern is given by the formula: $\Delta y

Vedclass · Accepted Answer

$0.192$

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(C) The distance between the first minima on both sides of the central maximum in a single slit diffraction pattern is given by the formula: $\Delta y = \frac{2 \lambda D}{a}$Given:Distance between first minima $\Delta y = 5 \,mm = 5 	imes 10^{-3} \,m$Distance of screen $D = 80 \,cm = 0.8 \,m$Wavelength $\lambda = 6000 \mathring{A} = 6000 	imes 10^{-10} \,m = 6 	imes 10^{-7} \,m$Substituting the values into the formula:$5 	imes 10^{-3} = \frac{2 	imes (6 	imes 10^{-7}) 	imes 0.8}{a}$Rearranging for the slit width $a$:$a = \frac{2 	imes 6 	imes 10^{-7} 	imes 0.8}{5 	imes 10^{-3}}$$a = \frac{9.6 	imes 10^{-7}}{5 	imes 10^{-3}}$$a = 1.92 	imes 10^{-4} \,m = 0.192 	imes 10^{-3} \,m$$a = 0.192 \,mm$

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