In a single throw of 2 dice,find the probabil | vedclass

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(B) When $2$ dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.The outcomes that result in a sum of $11$ are $(5, 6)$ and $(6

Vedclass · Accepted Answer

$\frac{1}{18}$

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(B) When $2$ dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.The outcomes that result in a sum of $11$ are $(5, 6)$ and $(6, 5)$.Thus,the number of favorable outcomes is $2$.The probability of an event is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.$	ext{Required probability} = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{2}{36} = \frac{1}{18}$.

In a single throw of $2$ dice,find the probability of getting a total of $11$.

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