In a single throw of 3 dice,find the probabil | vedclass

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(C) The total number of outcomes when throwing $3$ dice is $6^3 = 216$.Let $E$ be the event of getting a total of at least $5$. It is easier to calcul

Vedclass · Accepted Answer

$\frac{53}{54}$

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(C) The total number of outcomes when throwing $3$ dice is $6^3 = 216$.Let $E$ be the event of getting a total of at least $5$. It is easier to calculate the probability of the complement event $E'$,which is getting a total of less than $5$ (i.e.,a total of $3$ or $4$).Possible outcomes for a total of $3$: $(1, 1, 1)$ - $1$ case.Possible outcomes for a total of $4$: $(1, 1, 2), (1, 2, 1), (2, 1, 1)$ - $3$ cases.Total outcomes for $E'$ (sum is $3$ or $4$) $= 1 + 3 = 4$.$P(E') = \frac{4}{216} = \frac{1}{54}$.Therefore,$P(E) = 1 - P(E') = 1 - \frac{1}{54} = \frac{53}{54}$.

In a single throw of $3$ dice,find the probability of getting a total of at least $5$.

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