(C) step-up transformer increases the voltage,meaning $V_s > V_p$. Since the power in an ideal transformer is conserved $(P_p = P_s)$,we have $V_p I_p

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Current in the primary coil is more than current in the secondary coil

(C) step-up transformer increases the voltage,meaning $V_s > V_p$. Since the power in an ideal transformer is conserved $(P_p = P_s)$,we have $V_p I_p = V_s I_s$. Because $V_s > V_p$,it follows that $I_p > I_s$. Therefore,the current in the primary coil is greater than the current in the secondary coil.

Class 12 Physics Electromagnetic Induction Transformer

Easy

In a step-up transformer,which one of the following statements is correct?

MHT CET 2021 All MHT CET

A
Number of turns in the secondary coil is less than in primary coil
B
Voltage in secondary coil is less than in primary coil
C
Current in the primary coil is more than current in the secondary coil
D
Current in the primary coil is equal to current in the secondary coil

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MediumMHT CET 2021

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The ratio of secondary to primary turns is $9:4$. If power input is $P$, what will be the ratio of power output (neglect all losses) to power input?

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For an ideal transformer,if $N_S > N_P$,then . . . . . . .

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In a step-up transformer,which one of the following statements is correct?

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$A$ step-up transformer operates on $220 \,V$ and supplies a current of $2 \,A$. The ratio of primary and secondary windings is $1:20$. The current in the primary is (in $\,A$)

$A$ transformer has $100$ turns in the primary coil and carries $8$ $A$ current. If input power is $1$ $kW$, the number of turns in the secondary coil to have $500$ $V$ output will be

$A$ power transmission line feeds input power at $2300\; V$ to a step-down transformer with its primary windings having $4000$ turns. What should be the number of turns in the secondary in order to get output power at $230\; V$?

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