The ratio of secondary to primary turns is $9:4$. If power input is $P$, what will be the ratio of power output (neglect all losses) to power input?

$A$ transformer has $100$ turns in the primary coil and carries $8 \, A$ current. If the input power is $1 \, kW$, the number of turns required in the secondary coil to have $500 \, V$ output is:

In a step-up transformer,if the ratio of turns of primary to secondary is $1:10$ and the primary voltage is $230 \, V$. If the load current is $2 \, A$,then the current in the primary is.......$A$.

In an ideal step-up transformer,if the input voltage and input power are $V_1$ and $P_1$ respectively,and the output voltage and output power are $V_2$ and $P_2$ respectively,then

In a primary coil,a $5\,A$ current is flowing at $220\,V$. In the secondary coil,a voltage of $2200\,V$ is produced. The ratio of the number of turns in the secondary coil to the primary coil is:

An ideal transformer with a purely resistive load operates at $12\,kV$ on the primary side. It supplies electrical energy to a number of nearby houses at $120\,V$. The average rate of energy consumption in the houses served by the transformer is $60\,kW$. The value of the resistive load $(R_s)$ required in the secondary circuit will be $.........\,m\Omega$.