In a transistor,a change of $8.0\, mA$ in the emitter current produces a change of $7.8\, mA$ in the collector current. What change in the base current is necessary to produce the same change in the collector current? (in $\mu A$)

For a transistor,$\alpha$ and $\beta$ are given as $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$. Then the correct relation between $\alpha$ and $\beta$ is:

In a $p-n-p$ transistor working as a common base amplifier, when the current gain is $0.96$ and emitter current is $7.2 \,mA$, the base current is (in $\,mA$)

The graph between the input voltage $(V_{i})$ and the output voltage $(V_{o})$ of a transistor connected in common emitter configuration is shown in the figure. The active, saturation and cutoff regions of the transistor are respectively

In a transistor,the collector current is always less than the emitter current because:

$A$ transistor is operated in common emitter configuration at a constant collector voltage $V_C = 1.5 \, V$ such that a change in the base current from $100 \, \mu A$ to $150 \, \mu A$ produces a change in the collector current from $5 \, mA$ to $10 \, mA$. The current gain $\beta$ is: