In a transistor, comparing the doping of emitter, base, and collector, the part which is heavily doped and that which is lightly doped are respectively:

If a transistor having $\alpha = 0.9$ is used in $CE$ configuration, then for a change of $0.4 \text{ mA}$ in base current, what will be the change in collector current (in $\text{ mA}$)?

For the given bipolar junction transistor,find the approximate value of $I_B$,if $V_{CC} = 9 \ V$,$V_{BB} = 1.5 \ V$,$R_C = 13 \ k\Omega$,$R_E = 17 \ k\Omega$,and $\beta = 100$. (Assume the transistor is in active mode and $V_{BE} = 0.7 \ V$)

In a common emitter amplifier,the output resistance is $5000 \Omega$ and the input resistance is $2000 \Omega$. If the peak value of input signal voltage is $100 mV$ and $\beta=50$,then the peak value of output voltage is

In a $CE$ transistor amplifier,the audio signal voltage across the collector resistance of $2 \, k\Omega$ is $2 \, V$. If the base resistance is $1 \, k\Omega$ and the current amplification of the transistor is $100$,the input signal voltage is

In a $p-n-p$ transistor,