In a transistor,the collector current varies | vedclass

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(A) Given,collector current variation,$ \Delta I_{C} = 0.49 \,mA $.Emitter current variation,$ \Delta I_{E} = 0.50 \,mA $.We know that the base curren

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(A) Given,collector current variation,$ \Delta I_{C} = 0.49 \,mA $.Emitter current variation,$ \Delta I_{E} = 0.50 \,mA $.We know that the base current variation is given by $ \Delta I_{B} = \Delta I_{E} - \Delta I_{C} $.Substituting the values,$ \Delta I_{B} = 0.50 \,mA - 0.49 \,mA = 0.01 \,mA $.The current gain $ \beta $ is defined as the ratio of collector current change to base current change:$ \beta = \frac{\Delta I_{C}}{\Delta I_{B}} $.Substituting the values,$ \beta = \frac{0.49 \,mA}{0.01 \,mA} = 49 $.Therefore,the current gain $ \beta $ is $ 49 $.

In a transistor,the collector current varies by $ 0.49 \,mA $ and emitter current varies by $ 0.50 \,mA $. Current gain $ \beta $ measured is

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