In a triangle $ABC$ with usual notations,if $b \sin C(b \cos C + c \cos B) = 42$,then the area of triangle $ABC$ is:

  • A
    $42 \text{ sq.units}$
  • B
    $21 \text{ sq.units}$
  • C
    $24 \text{ sq.units}$
  • D
    $12 \text{ sq.units}$

Explore More

Similar Questions

In $\triangle ABC$,if $a: b: c = 4: 5: 6$,then $\cos A: \cos B: \cos C =$

With usual notations, in $\triangle ABC$, if $\cos C = \frac{\sin A}{2 \sin B}$, then which of the following is true?

If $R$ is the circumradius of $\triangle ABC$,then the area of $\triangle ABC$ is equal to $\ldots$.

In $\triangle ABC$,$m \angle B = \frac{\pi}{3}$ and $m \angle C = \frac{\pi}{4}$. Let point $D$ divide $BC$ internally in the ratio $1:3$. Then,the value of $\frac{\sin(\angle BAD)}{\sin(\angle CAD)}$ is

If $a, b$ and $c$ are the sides of a triangle such that $a^4 + b^4 + c^4 = 2c^2(a^2 + b^2)$,then the angle opposite to the side $c$ is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo