In a triangle ABC,right-angled at C,the value | vedclass

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(D) Given a right-angled triangle $ABC$ with the right angle at $C$.Let $a, b,$ and $c$ be the lengths of sides $BC, CA,$ and $AB$ respectively.From t

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$\frac{c^2}{ab}$

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(D) Given a right-angled triangle $ABC$ with the right angle at $C$.Let $a, b,$ and $c$ be the lengths of sides $BC, CA,$ and $AB$ respectively.From the Pythagoras theorem,we have $c^2 = a^2 + b^2$.In the right-angled triangle $ABC$:$	an A = \frac{	ext{opposite}}{	ext{adjacent}} = \frac{BC}{AC} = \frac{a}{b}$$	an B = \frac{	ext{opposite}}{	ext{adjacent}} = \frac{AC}{BC} = \frac{b}{a}$Therefore,$	an A + 	an B = \frac{a}{b} + \frac{b}{a}$$= \frac{a^2 + b^2}{ab}$Since $a^2 + b^2 = c^2$,we get:$= \frac{c^2}{ab}$

In a triangle $ABC$,right-angled at $C$,the value of $\tan A + \tan B$ is

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