In a triangle ABC,r_1 cot frac{A}{2} + r_2 co | vedclass

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(C) We know that the exradii are given by $r_1 = \frac{\Delta}{s-a}$,$r_2 = \frac{\Delta}{s-b}$,and $r_3 = \frac{\Delta}{s-c}$.Also,$\cot \frac{A}{2}

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$3s$

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(C) We know that the exradii are given by $r_1 = \frac{\Delta}{s-a}$,$r_2 = \frac{\Delta}{s-b}$,and $r_3 = \frac{\Delta}{s-c}$.Also,$\cot \frac{A}{2} = \sqrt{\frac{s(s-a)}{(s-b)(s-c)}} = \frac{s(s-a)}{\Delta}$.Substituting these into the expression:$r_1 \cot \frac{A}{2} + r_2 \cot \frac{B}{2} + r_3 \cot \frac{C}{2} = \left( \frac{\Delta}{s-a} \cdot \frac{s(s-a)}{\Delta} \right) + \left( \frac{\Delta}{s-b} \cdot \frac{s(s-b)}{\Delta} \right) + \left( \frac{\Delta}{s-c} \cdot \frac{s(s-c)}{\Delta} \right)$$= s + s + s = 3s$.

In a triangle $ABC$,$r_1 \cot \frac{A}{2} + r_2 \cot \frac{B}{2} + r_3 \cot \frac{C}{2} =$

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