In a triangle $ABC$,angle $A$ is greater than angle $B$. If the measures of angles $A$ and $B$ satisfy the equation $3\sin x - 4\sin^3 x - k = 0$ for $0 < k < 1$,then the measure of angle $C$ is:

  • A
    $\frac{\pi}{3}$
  • B
    $\frac{\pi}{2}$
  • C
    $\frac{2\pi}{3}$
  • D
    $\frac{5\pi}{6}$

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