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(D) The cathode is at $0 \, V$ and the grid is at $-2 \, V$. As the electron moves from the cathode to the grid,it experiences a retarding potential d

Vedclass · Accepted Answer

$83$

Vedclass · Answer

(D) The cathode is at $0 \, V$ and the grid is at $-2 \, V$. As the electron moves from the cathode to the grid,it experiences a retarding potential difference of $2 \, V$. Therefore,the loss in kinetic energy is $2 \, eV$. The kinetic energy of the electron after passing through the grid is $3 \, eV - 2 \, eV = 1 \, eV$. The potential difference between the plate $(80 \, V)$ and the grid $(-2 \, V)$ is $80 - (-2) = 82 \, V$. As the electron moves from the grid to the plate,it gains kinetic energy equal to the potential difference,which is $82 \, eV$. The final kinetic energy of the electron reaching the plate is $1 \, eV + 82 \, eV = 83 \, eV$.

In a triode,the cathode,grid,and plate are at potentials of $0 \, V$,$-2 \, V$,and $80 \, V$ respectively. Electrons are emitted from the cathode with an initial kinetic energy of $3 \, eV$. What is the energy of the electron when it reaches the plate in $eV$?

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