In alkene (ethene),the number of $sp^2$ hybridized carbon atoms is:

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    $0$

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The major product of this reaction is:

The major product formed in the following reaction is :
$CH_3CH=CHCH(CH_3)_2 \xrightarrow{HBr}$

What is the major product formed during the debromination of $meso-2,3-dibromobutane$?

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The product$(s)$ in the following sequence of reactions will be: $Me-C \equiv C-Me \xrightarrow[2. \text{dil. alkaline } KMnO_4]{1. Na/NH_3(liq.), \text{ethanol}, -33^\circ C}$ Product$(s)$

The reaction of an alkene $X$ with bromine produces a compound $Y$,which has $22.22 \% \ C$,$3.71 \% \ H$ and $74.07 \% \ Br$. The ozonolysis of alkene $X$ gives only one product. The alkene $X$ is,
[Given,atomic mass of $C = 12$; $H = 1$; $Br = 80$ ]

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