The reaction of an alkene X with bromine prod | vedclass

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(C) The empirical formula of $Y$ is calculated as follows:Element$\%$ of elementAt massMolesRatio$C$$22.22$$12$$1.85$$2$$H$$3.71$$1$$3.71$$4$$Br$$74.0

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$2$-butene

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(C) The empirical formula of $Y$ is calculated as follows:Element$\%$ of elementAt massMolesRatio$C$$22.22$$12$$1.85$$2$$H$$3.71$$1$$3.71$$4$$Br$$74.07$$80$$0.92$$1$The empirical formula is $C_2H_4Br$. Since the reaction is $X + Br_2 \rightarrow Y$,the molecular formula of $Y$ is $C_4H_8Br_2$.The alkene $X$ is $C_4H_8$. Ozonolysis of $X$ gives only one product,which implies $X$ is symmetric. Among the options,$2$-butene $(CH_3-CH=CH-CH_3)$ is symmetric and yields two molecules of acetaldehyde upon ozonolysis.

The reaction of an alkene $X$ with bromine produces a compound $Y$,which has $22.22 \% \ C$,$3.71 \% \ H$ and $74.07 \% \ Br$. The ozonolysis of alkene $X$ gives only one product. The alkene $X$ is,
[Given,atomic mass of $C = 12$; $H = 1$; $Br = 80$ ]

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The reaction of an alkene $X$ with bromine produces a compound $Y$,which has $22.22 \% \ C$,$3.71 \% \ H$ and $74.07 \% \ Br$. The ozonolysis of alkene $X$ gives only one product. The alkene $X$ is,[Given,atomic mass of $C = 12$; $H = 1$; $Br = 80$ ]