In amplitude modulation,the message signal V_ | vedclass

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(A) The message signal is given by $V_{m}(t) = 10 \sin(2 \pi 	imes 10^{5} t)$.Comparing this with the standard form $V_{m}(t) = A_{m} \sin(2 \pi f_{m

Vedclass · Accepted Answer

$200$

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(A) The message signal is given by $V_{m}(t) = 10 \sin(2 \pi 	imes 10^{5} t)$.Comparing this with the standard form $V_{m}(t) = A_{m} \sin(2 \pi f_{m} t)$,we get the frequency of the message signal $f_{m} = 10^{5} 	ext{ Hz} = 100 	ext{ kHz}$.In amplitude modulation,the modulated signal consists of the carrier frequency $f_{c}$,the lower sideband frequency $(f_{c} - f_{m})$,and the upper sideband frequency $(f_{c} + f_{m})$.The bandwidth of an amplitude-modulated signal is defined as the difference between the upper sideband frequency and the lower sideband frequency:$	ext{Bandwidth} = (f_{c} + f_{m}) - (f_{c} - f_{m}) = 2 f_{m}$.Substituting the value of $f_{m}$:$	ext{Bandwidth} = 2 	imes 100 	ext{ kHz} = 200 	ext{ kHz}$.Thus,$\alpha = 200$.

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