In an npn transistor,10^{10} electrons enter | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The emitter current $I_{E}$ is given by the rate of flow of charge: $I_{E} = \frac{n \cdot e}{t}$.Given $n = 10^{10}$ electrons,$e = 1.6 	imes 10

Vedclass · Accepted Answer

$0.99$ and $99$

Vedclass · Answer

(D) The emitter current $I_{E}$ is given by the rate of flow of charge: $I_{E} = \frac{n \cdot e}{t}$.Given $n = 10^{10}$ electrons,$e = 1.6 	imes 10^{-19} \ C$,and $t = 10^{-8} \ s$.$I_{E} = \frac{10^{10} 	imes 1.6 	imes 10^{-19}}{10^{-8}} = 1.6 	imes 10^{-1} \ A = 0.16 \ A$.Since $1\%$ of electrons are lost in the base,the base current $I_{B} = 0.01 \ I_{E}$.The collector current $I_{C}$ is the remaining current: $I_{C} = I_{E} - I_{B} = I_{E} - 0.01 \ I_{E} = 0.99 \ I_{E}$.The fraction of current entering the collector is $\frac{I_{C}}{I_{E}} = 0.99$.The current amplification factor $\beta$ is defined as $\beta = \frac{I_{C}}{I_{B}} = \frac{0.99 \ I_{E}}{0.01 \ I_{E}} = 99$.

In an $npn$ transistor,$10^{10}$ electrons enter the emitter in $10^{-8}$ second. If $1\%$ of electrons are lost in the base,the fraction of current that enters the collector and the current amplification factor are respectively:

Similar Questions

The input resistance of a common-emitter amplifier is $2 \, k\Omega$ and a.c. current gain is $20$. If the load resistor used is $5 \, k\Omega$,calculate the transconductance of the transistor used in $\Omega^{-1}$.

An $n-p-n$ transistor has three leads $A, B$ and $C$. Connecting $B$ and $C$ by moist fingers,$A$ to the positive lead of an ammeter,and $C$ to the negative lead of the ammeter,one finds large deflection. Then,$A, B$ and $C$ refer respectively to

In a $CE$ circuit,the collector of a transistor is kept at a constant voltage $V_C = 1.5 \ V$. When the base current changes from $100 \ \mu A$ to $150 \ \mu A$,the collector current changes from $5 \ mA$ to $10 \ mA$. The current gain $\beta$ for this transistor is:

If $X, Y$ and $Z$ are the sizes of the emitter,base and collector of a transistor respectively,then

The typical output characteristics curve for a transistor working in the common-emitter configuration is shown in the figure. The estimated current gain from the figure is

Vedclass Test Series

Exam Paper Generator

Online Exam Module