In a CE circuit,the collector of a transistor | vedclass

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(D) The change in base current is given by $\Delta I_B = 150 \ \mu A - 100 \ \mu A = 50 \ \mu A = 50 	imes 10^{-6} \ A$. The change in collector curr

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$100$

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(D) The change in base current is given by $\Delta I_B = 150 \ \mu A - 100 \ \mu A = 50 \ \mu A = 50 	imes 10^{-6} \ A$. The change in collector current is given by $\Delta I_C = 10 \ mA - 5 \ mA = 5 \ mA = 5 	imes 10^{-3} \ A$. The current gain $\beta$ is defined as the ratio of the change in collector current to the change in base current: $\beta = \frac{\Delta I_C}{\Delta I_B} = \frac{5 	imes 10^{-3} \ A}{50 	imes 10^{-6} \ A} = \frac{5000 	imes 10^{-6}}{50 	imes 10^{-6}} = 100$.

In a $CE$ circuit,the collector of a transistor is kept at a constant voltage $V_C = 1.5 \ V$. When the base current changes from $100 \ \mu A$ to $150 \ \mu A$,the collector current changes from $5 \ mA$ to $10 \ mA$. The current gain $\beta$ for this transistor is:

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