In an $EMW$,the phase difference between electric and magnetic field vectors $\vec E$ and $\vec B$ is:

An electromagnetic wave has an electric field given by the expression (in Cartesian coordinates) $\vec E(x,t) = 6.0\,\cos(1 \times 10^7x - 3 \times 10^{15}t)\hat z$. What is the direction of the magnetic field at time $t = 0$ and position $x = 0$?

The ratio of the average electric energy density to the total average energy density of an electromagnetic wave is:

An electromagnetic wave with frequency $\omega$ and wavelength $\lambda$ travels in the $+y$ direction. Its magnetic field is along the $+x$ axis. The vector equation for the associated electric field (of amplitude $E_0$) is:

The electric field part of an electromagnetic wave in a medium is represented by $E_x = 0$; $E_y = 2.5 \frac{N}{C} \cos \left[ (2\pi \times 10^6 \frac{rad}{s})t - (\pi \times 10^{-2} \frac{rad}{m})x \right]$; $E_z = 0$. The wave is:

$A$ plane electromagnetic wave is incident on a plane surface of area $A$ normally,and is perfectly reflected. If energy $E$ strikes the surface in time $t$,then the average pressure exerted on the surface is ($c=$ speed of light).