In an elevator,a spring clock of time period | vedclass

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(C) The time period of a spring-mass system is given by $T_S = 2 \pi \sqrt{\frac{m}{k}}$. This formula does not contain the acceleration due to gravit

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$T_S$ remains same,$T_P$ decreases

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(C) The time period of a spring-mass system is given by $T_S = 2 \pi \sqrt{\frac{m}{k}}$. This formula does not contain the acceleration due to gravity $g$,so $T_S$ remains unchanged when the elevator accelerates.The time period of a simple pendulum is given by $T_P = 2 \pi \sqrt{\frac{\ell}{g_{eff}}}$.When the elevator accelerates upwards with acceleration $a$,the effective acceleration due to gravity becomes $g_{eff} = g + a$.Since $g_{eff} > g$,the denominator increases,which causes the time period $T_P$ to decrease.Therefore,$T_S$ remains the same and $T_P$ decreases.

In an elevator,a spring clock of time period $T_S$ (mass attached to a spring) and a pendulum clock of time period $T_P$ are kept. If the elevator accelerates upwards,what happens to their time periods?

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