In an examination,30 % of the total students | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the total number of students be $100$.Let $H$ be the set of students who failed in Hindi and $E$ be the set of students who failed in English.

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(C) Let the total number of students be $100$.Let $H$ be the set of students who failed in Hindi and $E$ be the set of students who failed in English.Given: $n(H) = 30$,$n(E) = 45$,and $n(H \cap E) = 20$.We need to find the number of students who failed in at least one subject,which is given by the union $n(H \cup E)$.Using the formula: $n(H \cup E) = n(H) + n(E) - n(H \cap E)$.$n(H \cup E) = 30 + 45 - 20 = 55$.So,$55 \%$ of students failed in at least one subject.The percentage of students who passed in both subjects is the complement of those who failed in at least one subject.Percentage passed $= 100 \% - 55 \% = 45 \%$.

In an examination,$30 \%$ of the total students failed in Hindi,$45 \%$ failed in English,and $20 \%$ failed in both the subjects. Find the percentage of those who passed in both the subjects. (in $\%$)

Similar Questions

If $U = \{2, 3, 4, 5, 6, 7, 8, 9, 10, 11\}$,$A = \{2, 4, 7\}$,$B = \{3, 5, 7, 9, 11\}$,and $C = \{7, 8, 9, 10, 11\}$,compute: $(A \cap U) \cap (B \cup C)$.

If $f(x) = \cos([\pi^2]x) + \cos([- \pi^2]x)$,then which of the following is true?

The range of $f(x) = \cos 2x - \sin 2x$ contains the set

In a class of $50$ students,$35$ opted for Mathematics and $37$ opted for Biology. How many have opted for both Mathematics and Biology? How many have opted for only Mathematics? (Assume that each student has to opt for at least one of the subjects).

$A - (A - B)$ is equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module