In an isobaric process,the work done by a dia | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For an isobaric process,the work done $W$ and heat supplied $Q$ are given by:$W = n R \Delta T$$Q = n C_p \Delta T$Since $C_p = \frac{f}{2} R + R

Vedclass · Accepted Answer

$35$

Vedclass · Answer

(A) For an isobaric process,the work done $W$ and heat supplied $Q$ are given by:$W = n R \Delta T$$Q = n C_p \Delta T$Since $C_p = \frac{f}{2} R + R = (\frac{f}{2} + 1) R$,we have:$\frac{W}{Q} = \frac{n R \Delta T}{n (\frac{f}{2} + 1) R \Delta T} = \frac{1}{\frac{f}{2} + 1}$For a diatomic gas,the degrees of freedom $f = 5$.Substituting $f = 5$:$\frac{W}{Q} = \frac{1}{\frac{5}{2} + 1} = \frac{1}{\frac{7}{2}} = \frac{2}{7}$Therefore,$Q = \frac{7}{2} W$.Given $W = 10 \ J$,we get:$Q = \frac{7}{2} 	imes 10 = 35 \ J$.

In an isobaric process,the work done by a diatomic gas is $10 \ J$. The heat given to the gas will be (in $J$):

Similar Questions

The ratio of specific heats of a gas is $\gamma$. The change in internal energy of one mole of the gas, when the volume changes from $V$ to $2V$ at constant pressure $p$, is:

$A$ monoatomic ideal gas is heated at constant pressure. The percentage of total heat used in changing the internal energy is (in $\%$)

Which relation is correct for an isochoric process?

Which one of the following $p-V$ diagrams is correct for an isochoric process?

The thermodynamic process in which the work done on or by the gas is zero is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module