In an oscillating LC circuit,the maximum char | vedclass

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(D) In an oscillating $LC$ circuit,the total energy $U$ is constant and is given by the maximum energy stored in the capacitor: $U = \frac{1}{2} \frac

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$\frac{Q}{\sqrt{2}}$

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(D) In an oscillating $LC$ circuit,the total energy $U$ is constant and is given by the maximum energy stored in the capacitor: $U = \frac{1}{2} \frac{Q^2}{C}$.When the energy is stored equally between the electric field (capacitor) and the magnetic field (inductor),the energy in the capacitor $U_E$ is half of the total energy $U$.$U_E = \frac{1}{2} U$Substituting the expressions for energy: $\frac{1}{2} \frac{q^2}{C} = \frac{1}{2} \left( \frac{1}{2} \frac{Q^2}{C} \right)$Simplifying the equation: $\frac{q^2}{C} = \frac{1}{2} \frac{Q^2}{C}$$q^2 = \frac{Q^2}{2}$$q = \frac{Q}{\sqrt{2}}$Therefore,the charge on the capacitor when the energy is shared equally is $\frac{Q}{\sqrt{2}}$.

In an oscillating $LC$ circuit,the maximum charge on the capacitor is $Q$. The charge on the capacitor when the energy is stored equally between the electric and magnetic fields is

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