In the chromyl chloride test for the confirma | vedclass

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Question

(A) In the chromyl chloride test,$Cl^{-}$ reacts to form chromyl chloride $(CrO_2Cl_2)$,which dissolves in a basic medium to form a yellow solution co

Vedclass · Accepted Answer

$+6$

Vedclass · Answer

(A) In the chromyl chloride test,$Cl^{-}$ reacts to form chromyl chloride $(CrO_2Cl_2)$,which dissolves in a basic medium to form a yellow solution containing chromate ions $(CrO_4^{2-})$.When this yellow solution is acidified and treated with $10\% H_2O_2$ in the presence of amyl alcohol,it forms a blue-colored peroxo compound,chromium pentoxide $(CrO_5)$.The structure of $CrO_5$ (butterfly structure) contains one double-bonded oxygen atom (oxidation state $-2$) and four peroxo oxygen atoms (each with oxidation state $-1$).Let the oxidation state of $Cr$ be $x$.$x + 1(-2) + 4(-1) = 0$$x - 2 - 4 = 0$$x = +6$Thus,the oxidation state of chromium in $CrO_5$ is $+6$.

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