In column-$I$,diagrams of the carbonyl group are given,and in column-$II$,their descriptions are given. Match column-$I$ with the correct option given in column-$II$.
| Column-$I$ (Drawing diagram) | Column-$II$ (Description) |
| :--- | :--- |
| $(A)$ Resonance structures of carbonyl group | $(i)$ In carbon-oxygen,$\pi$-electron clouds are present on the upper and lower parts of the plane. |
| $(B)$ Geometry of carbonyl group | (ii) Non-bonding $2p$ orbital which is not taking part in hybridization of carbonyl carbon and $2p$ orbital of oxygen containing one electron are parallel to each other and perpendicular to the plane. |
| $(C)$ $\sigma$-bonding in carbonyl group | (iii) Hybridization of carbonyl carbon is $sp^2$ and it has a planar triangular structure and bond angle approximately $120^{\circ}$. |
| $(D)$ $\pi$-bonding in carbonyl group | (iv) Two hybrid structures of the carbonyl group indicate that the carbon-oxygen bond is polar in nature and also the carbon atom is an electrophilic centre and the oxygen atom is a nucleophilic centre. |

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(A) The correct matching is as follows:
$(A)$ Resonance structures of the carbonyl group represent the polarity of the bond,where carbon acts as an electrophilic centre and oxygen as a nucleophilic centre. Thus,$A \rightarrow iv$.
$(B)$ The geometry shows the $sp^2$ hybridized carbon with a planar triangular structure and bond angles of approximately $120^{\circ}$. Thus,$B \rightarrow iii$.
$(C)$ The $\sigma$-bonding involves the overlap of orbitals forming the skeleton of the carbonyl group. Thus,$C \rightarrow ii$ (referring to the non-bonding $2p$ orbitals perpendicular to the plane).
$(D)$ The $\pi$-bonding involves the overlap of $p$-orbitals above and below the plane. Thus,$D \rightarrow i$.
Therefore,the correct match is $A$ $\rightarrow iv, B$ $\rightarrow iii, C$ $\rightarrow ii, D$ $\rightarrow i$.

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