In common emitter mode of a transistor, the d.c. current gain $(\beta)$ is $20$ and the emitter current $(I_E)$ is $7 \text{ mA}$. The collector current $(I_C)$ is: (in $/3 \text{ mA}$)

For a transistor,the parameter $\beta = 99$. The value of the parameter $\alpha$ is

In an $n-p-n$ transistor, $95 \%$ of emitted electrons reach the collector. If the base current is $2 \text{ mA}$, then the collector current is (in $\text{ mA}$)

$A$ transistor is connected in common emitter $(CE)$ configuration. The collector supply is $8\ V$ and the voltage drop across a resistor of $800\,\Omega$ in the collector circuit is $0.5\ V$. If the current gain factor $\alpha$ is $0.96$,find the base current in $\mu A$.

If $\alpha$ is the current gain in a $CB$ circuit and $\beta$ is the current gain in a $CE$ circuit,then $\alpha / \beta$ = ......

In the given circuit, a voltmeter $V$ is connected across a bulb $B$. If the value of the resistor $R$ is increased, what happens?