In a diamond crystal,each carbon atom is link | vedclass

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Question

(C) Diamond crystallizes in a face-centered cubic $(fcc)$ structure where carbon atoms occupy all the lattice points of the $fcc$ unit cell.The number

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(C) Diamond crystallizes in a face-centered cubic $(fcc)$ structure where carbon atoms occupy all the lattice points of the $fcc$ unit cell.The number of atoms at the corners is $8 	imes \frac{1}{8} = 1$.The number of atoms at the face centers is $6 	imes \frac{1}{2} = 3$.Additionally,carbon atoms occupy $50\%$ of the tetrahedral voids. In an $fcc$ unit cell,there are $8$ tetrahedral voids.Therefore,the number of atoms in tetrahedral voids is $8 	imes \frac{1}{2} = 4$.Total number of carbon atoms per unit cell = $1 + 3 + 4 = 8$.

In a diamond crystal,each carbon atom is linked with other carbon atoms. The number of carbon atoms in a diamond unit cell is:

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