In each of the following,a and d for an A.P. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The general form of an $A.P.$ is $a, a+d, a+2d, a+3d, \ldots$Given $a = \frac{15}{2}$ and $d = \frac{3}{2}$.First term $T_1 = a = \frac{15}{2} = 7

Vedclass · Accepted Answer

$\frac{15}{2}, 9, \frac{21}{2}, 12, \ldots$

Vedclass · Answer

(A) The general form of an $A.P.$ is $a, a+d, a+2d, a+3d, \ldots$Given $a = \frac{15}{2}$ and $d = \frac{3}{2}$.First term $T_1 = a = \frac{15}{2} = 7.5$.Second term $T_2 = a + d = \frac{15}{2} + \frac{3}{2} = \frac{18}{2} = 9$.Third term $T_3 = a + 2d = \frac{15}{2} + 2(\frac{3}{2}) = \frac{15}{2} + 3 = \frac{15+6}{2} = \frac{21}{2} = 10.5$.Fourth term $T_4 = a + 3d = \frac{15}{2} + 3(\frac{3}{2}) = \frac{15+9}{2} = \frac{24}{2} = 12$.Thus,the $A.P.$ is $\frac{15}{2}, 9, \frac{21}{2}, 12, \ldots$The general term is $T_n = a + (n-1)d = \frac{15}{2} + (n-1)\frac{3}{2} = \frac{15 + 3n - 3}{2} = \frac{3n + 12}{2}$.

In each of the following,$a$ and $d$ for an $A.P.$ are given. Find the $A.P.$ in each case. $a = \frac{15}{2}, \quad d = \frac{3}{2}$

Similar Questions

In an $AP$,if $d = -4$,$n = 7$,and $a_{n} = 4$,then $a$ is

Verify that each of the following is an $AP$,and then write its next three terms.
$a+b, (a+1)+b, (a+1)+(b+1), \ldots$

For the $A.P.$ $-2, -4, -6, -8, \ldots,$ the common difference is............

The $n^{th}$ term of an $A.P.$ is given by $T_{n} = 7 - 3n$. Find the sum of the first $25$ terms of the $A.P.$

How many terms of the $AP: -15, -13, -11, \ldots$ are needed to make the sum $-55$? Explain the reason for the double answer.

Vedclass Test Series

Exam Paper Generator

Online Exam Module