In the fifth group of qualitative analysis,(N | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $Na_2CO_3$ is a strong electrolyte that provides a high concentration of $CO_3^{2-}$ ions. This high concentration of carbonate ions causes the pr

Vedclass · Accepted Answer

$MgCO_3$ will be precipitated out in the fifth group

Vedclass · Answer

(C) $Na_2CO_3$ is a strong electrolyte that provides a high concentration of $CO_3^{2-}$ ions. This high concentration of carbonate ions causes the precipitation of $Mg^{2+}$ ions as $MgCO_3$ along with the fifth group radicals $(Ba^{2+}, Sr^{2+}, Ca^{2+})$. $(NH_4)_2CO_3$ is a weaker electrolyte and provides a lower concentration of $CO_3^{2-}$ ions,which is sufficient to exceed the solubility product $(K_{sp})$ of the fifth group carbonates but not $MgCO_3$.

In the fifth group of qualitative analysis,$(NH_4)_2CO_3$ is added to precipitate out the carbonates. We do not add $Na_2CO_3$ because

Similar Questions

The reagent used in the qualitative analysis of the $IV^{th}$ group basic radicals is:

The ion that can be precipitated by $HCl$ as well as $H_2S$ is

Three separate samples of a solution of a single salt gave these test results: one formed a white precipitate with excess ammonia solution,one formed a white precipitate with dilute $NaCl$ solution,and one formed a black precipitate with $H_2S$. The salt could be:

$MgSO_4$ on reaction with $NH_4OH$ and $Na_2HPO_4$ forms a white crystalline precipitate. What is its formula?

Which of the following statements is incorrect?

Vedclass Test Series

Exam Paper Generator

Online Exam Module