In the given figure (a square),identify the co-initial vectors.
(N/A) Co-initial vectors are vectors that originate from the same initial point.
Looking at the square,vectors $\vec{a}$ and $\vec{d}$ originate from the top-left corner of the square.
Therefore,$\vec{a}$ and $\vec{d}$ are co-initial vectors.
Looking at the square,vectors $\vec{a}$ and $\vec{d}$ originate from the top-left corner of the square.
Therefore,$\vec{a}$ and $\vec{d}$ are co-initial vectors.
Explore More
Similar Questions
Write two different vectors having the same magnitude.
Easy
View SolutionThe points whose position vectors are $2\hat{i}+3\hat{j}+4\hat{k}$, $3\hat{i}+4\hat{j}+2\hat{k}$, and $4\hat{i}+2\hat{j}+3\hat{k}$ are the vertices of
If the position vectors of points $A, B, C$ are respectively $\hat{i}, \hat{j}, \hat{k}$ and $\vec{AB} = \vec{CX}$,then the position vector of point $X$ is:
Difficult
View SolutionIf $\vec{a}=\vec{b}+\vec{c},$ then is it true that $|\vec{a}|=|\vec{b}|+|\vec{c}|$ ? Justify your answer.
Medium
View SolutionWhich of the following vectors is equally inclined with the coordinate axes?
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo