In the figure,if AB parallel CD,angle APQ = 5 | vedclass

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(A) Given: $AB \parallel CD$,$\angle APQ = 50^o$,and $\angle PRD = 127^o$.$1$. Since $AB \parallel CD$ and $PQ$ is a transversal,the alternate interio

Vedclass · Accepted Answer

$x = 50^o$ and $y = 77^o$

Vedclass · Answer

(A) Given: $AB \parallel CD$,$\angle APQ = 50^o$,and $\angle PRD = 127^o$.$1$. Since $AB \parallel CD$ and $PQ$ is a transversal,the alternate interior angles are equal.Therefore,$\angle PQR = \angle APQ$.Given $\angle APQ = 50^o$,so $x = 50^o$.$2$. Since $AB \parallel CD$ and $PR$ is a transversal,the alternate interior angles are equal.Therefore,$\angle APR = \angle PRD$.Given $\angle PRD = 127^o$,so $\angle APR = 127^o$.We know that $\angle APR = \angle APQ + \angle QPR$.Substituting the values,$127^o = 50^o + y$.$y = 127^o - 50^o = 77^o$.Thus,$x = 50^o$ and $y = 77^o$.

In the figure,if $AB \parallel CD$,$\angle APQ = 50^o$ and $\angle PRD = 127^o$,find $x$ and $y$.

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